/* ------------------- begin IP Block script ------------------- Block IP address script Points to php script on blog.racetotheright.com IP addresses are within the script ---------- */ /* -------------------- end IP Block script ------------------- */

Thursday, February 23, 2006

Jon's MENSA Question of the Day

--posted by JRJ on 2/23/2006

(You may have seen this in a slightly different form, but this version has an unusual twist to it.) It was a bring-your-own-food party, but not everybody could contribute food. The agreement was that those who couldn't bring edibles would chip in some cash. Sally brought a certain number of pies, Jane brought one more than Sally, and Hector brought one more than Jane. William brought nothing, but asked them to divide the nice little pies equally, and he would pay. The four split the pies evenly. There was a total of a dozen pies, each worth $1.00. How much should each of them get or pay?

Labels:

3 Comments:

Blogger Dan S. said...

12 pies for 4 people, so each is responsible for 3.

Sally brought 3, so she's even.

Jane brought 4, so she should get $1 back.

Hector brought 5, so he should get $2 back.

William brought none (damn slacker!), so he needs to pony up $3 ($1 to Jane, $2 to Hector).

February 23, 2006  
Blogger JRJ said...

CORRECT (45%)

February 23, 2006  
Blogger LearnedFoot said...

Uh, WRONG!

The mensa who wrote this one is obviously not a lawyer. The critical part of the question reads:

"The agreement was that those who couldn't bring edibles would chip in some cash."

Since William was the only person "who couldn't bring edibles" he is the only one that is required to pay, per the agreement.

February 24, 2006  

Post a Comment

<< Home